TUTORIAL QUESTION OF EARTHWORK CALCULATION
Do all the Numerical problems in standard
Earthwork Format of calculation/ in MS-Excel.
Q1. Using Mean Area Method,
Workout the Quantity of Earthwork for an embankment of 150m long and
10m wide at the top. Side slope is 2:1 and depth at each 30m interval are 0.60, 1.20, 1.40, 1.60, 1.40, and
1.60m. Ans: -2572.8 m3
Q2
Calculate the quantity of earthwork
if the depths for road work for 210m length with chainage of measurement at
every 30m interval is surveyed as: 1.6m, 1.69m, 1.73m, 1.74m, 1.66m, 1.76m,
1.88m,1.60m whose side slope is 2:1 and formation width is 12m (solve it using
both mid-sectional and Mean Sectional method separately). Ans:
- 5588.44 m3
Q3. Calculate the Quantity of earthwork for bank of canal
from the following data: -
Top width 2m; R.L of Top of bank is
103.00;
side slopes: - 2 Hz
to 1 Vt @one side
2.5 Hz to 1 Vt @other side *use
Prismoidal formula
|
Chainage |
50 |
60 |
70 |
80 |
90 |
|
R.L
of G. L |
101.50 |
101.00 |
99.00 |
98.00 |
96.50 |
Ans: -1735.32m3
Q4.
Workout the quantity of the earthwork
for an embankment 120m long and 10 m wide at the top, side slope is 2:1 and
depth at each 30 m interval are 0.4m,0.6m,1.4m,1.2m,0.8m. (use all method
separately). Ans:-1389.6
m3
Q5.
Workout the quantity of the earthwork
for an embankment 150m long and 10 m wide at the top, side slope is 2:1 and
depth at each 25 m interval are 0.6m, 1.2m, 1.4m, 1.6m, 1.4m, 1.6m ,1.5m. Use
Prismoidal Method. V=L/6[A1+A2+4.Am] Ans:-2647.26m3
Q6. An embankment of width 10 m and side slopes 1
½:1 is required to be made on a ground which is level in a direction transverse
to the centre line. The central heights at 40 m intervals are: - 0.90,1.25,2.15,2.50,1.85,1.35, and 0.85
Calculate the volume of earth work according to
i) Trapezoidal Method and
ii) Simpson's Method Ans:-5096.4
m3 and 5142.9 m3
Q7. Explain
the formula to calculate the area of trapezoidal section as shown in figure of
Q1.
write down the formulas to calculate the earthwork.
a) Mid-section Area method b)
Mean sectional area method
c)Prismoidal method/Simpson's method d) Trapezoidal Method/End Area Method
Q8. Calculate the quantity of the earthwork from the
following data.
Width of formation is 10m,side slope cutting and
filling is 1:1 and 2:1 resp.
|
Chainage |
0+000 |
0+050 |
0+100 |
0+150 |
0+200 |
|
RL. Ground |
103.7 |
103.3 |
102.7 |
102.1 |
101.6 |
Q9. Prepare an estimate of earthwork in cutting and filling of the portion of the road from given data.
Road width is 10m; side slope in cutting and filling is 1.5: 1 and 2:1 respectively.
Downward gradient 1 in 150
|
Chainage |
0 |
30 |
60 |
90 |
|
G. L |
102 |
104 |
103 |
99 |
|
F. L |
100 |
….. |
….. |
….. |
ADDITIONAL PRACTICE QUESTION
1. Calculate the quantity of earthwork for the portion of a road with following data:
Length
of road is 70m
Formation
width is 10m
depth(d1)
= 2m
depth(d2)
= 3m
Side slope= 2:1
2. Estimate the quantity of earthwork for the road between
two stations A and B with following data:
Width
of formation level =8m and side slope is 1.5:1. Data of field book for the
portion of the road are as follows:
|
Chainage |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
|
G. L |
121.9 |
123 |
122.6 |
120.9 |
119.6 |
119 |
118.4 |
|
F. L |
121.2 |
121.6 |
122 |
121.6 |
121.2 |
120.8 |
120.4 |
3. Estimate the quantity of earthwork of an embankment
120m long, 8m wide road whose side slope is 2:1. The central height from 0 to
every 30m are 0.6m, 1.2m, 1.6m, 2.0m and 1.3m. (Use: - mid-sectional, mean
sectional area & Prismoidal method).
4. Work out the quantities of the earthwork in both
embankment(filling) and cutting for the length of 270m, from the following
data:
Formation
width of road =12m
Side
slope of the road in embankment(filling)=2:1
Side
slope in cutting =1.5:1
|
Chainage |
0 |
30 |
60 |
90 |
120 |
150 |
180 |
210 |
240 |
270 |
|
G. L |
102 |
102.35 |
102.6 |
102.8 |
103 |
102.65 |
102.2 |
101.5 |
101.2 |
100.65 |
|
F. L |
101.5 |
101.65 |
101.8 |
101.95 |
102.1 |
102.25 |
102.4 |
102.15 |
101.9 |
101.65 |
5. Estimate the quantity of the earthwork from chainage
10 to 15 measured with 20m chain. The data obtained are as follows: -
|
Chainage |
10 |
11 |
12 |
13 |
14 |
15 |
|
G. L
above datum |
188.1 |
187.74 |
188.2 |
190.4 |
190.75 |
190.2 |
The formation level at chainage 10 is 188.5m and
the road has rising gradient of 1 in 100. Formation width of the road is 10m
and side slope is 1:1 in cutting and 2:1 in banking. Draw the longitudinal
profile of this road as well showing the depths and reduced level.
*Last Submission date: -2080/04/20
Best
Wishes
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